Question

What is the force on a 1,000 kg elevator that is falling freely at 9.8 m/s 2 ? What is the force on a 1,000 kg elevator that is falling freely at 9.8 m/s 2 ?

Answer 1

9800 Newtons

Step-by-step explanation:

The force on a 1,000 kg elevator that is falling freely at 9.8 m/s^2 (acceleration due to gravity) is equal to the gravitational force acting on it.

The formula for calculating gravitational force is:

F = m * g

Where:

F = Force (in Newtons, N)

m = Mass of the object (in kilograms, kg)

g = Acceleration due to gravity (approximately 9.8 m/s^2 on the surface of the Earth)

Plugging in the values:

F = 1,000 kg * 9.8 m/s^2 = 9,800 N

So, the force on the 1,000 kg elevator falling freely at 9.8 m/s^2 is 9,800 Newtons, directed downward.