Question

For the reaction

X(g)+2Y(g)⇌3Z(g)

Kp = 1.51×10−2 at a temperature of 163 ∘C .

.KcCalculate the value of Kc

Answer 1

The reaction X(g)+2Y(g) ⇌ 3Z(g) has no change in mole numbers, so Kp = Kc. Hence, Kc is 1.51 x 10^-2.

Step-by-step explanation:

The relationship between Kp and Kc is given by the equation Kp = Kc*(RT)^∆n, where R is the universal gas constant (0.0821 L atm / mol K), T is the temperature in Kelvin, and ∆n is the change in mole numbers of the gaseous reactants and products.

Convert the temperature from Celsius to Kelvin. So, T = 163 + 273.15 = 436.15 K.

For the reaction X(g)+2Y(g)⇌3Z(g), the change in mole numbers (∆n) is: 3 moles (gaseous products) - 3 moles (gaseous reactants) = 0.

Since ∆n is 0, the equation simplifies to Kp = Kc. Hence, Kc = 1.51 × 10^-2.

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