Question

An ox exerts a forwards force of 7100 N. If the ox has a weight of 8000 N, what is the minimum coefficient of static friction? (HINT: if there was no static friction the ox would slip and not move forward, what friction is required to allow the ox to move without slipping)

Answer 1

Given data

*An ox exerts a forwards force is F = 7100 N

*An ox has weight is N = 8000 N

The formula for the minimum coefficient of static friction is given as

`\begin{gathered} F=\mu_sN \\ \mu_s=(F)/(N) \end{gathered}`

Substitute the known values in the above expression as

`\begin{gathered} \mu_s=(7100)/(8000) \\ =0.887 \end{gathered}`

Hence, the minimum coefficient of static friction is 0.887