Question

The left and right page numbers of an open book are two consecutive integers whose sum is 141. Find these page numbers.

The smaller page number is :


The bigger page number is :

Answer 1

Let's call the smaller page number "x" and the larger page number "x + 1" since they are two consecutive integers. According to the problem, their sum is 141:

x + (x + 1) = 141

Now, combine like terms:

2x + 1 = 141

Subtract 1 from both sides to isolate 2x:

2x = 141 - 1

2x = 140

Now, divide both sides by 2 to find the value of x:

x = 140 / 2

x = 70

So, the smaller page number is 70, and the larger page number is x + 1, which is 71.

Explanation:

Answer 2

Smaller page number: 70

Bigger page number: 71

Explanation:

Let x be the smaller page number.

Then the bigger page number is x + 1.

We know that the sum of the two page numbers is 141.

x + (x + 1) = 141

Combining like terms, we get:

2x + 1 = 141

Subtracting 1 from both sides, we get:

2x + 1 - 1 = 141 - 1

2x = 140

Dividing both sides by 2, we get:

`\sf (2x)/(2) = (140)/(2)`

x = 70

Therefore, the smaller page number is 70.

The bigger page number is x + 1 = 70 + 1 = 71.