203k views
2 votes
Maya, Ahmad, and Joe served a total of 75 orders Monday at the school cafeteria. Joe served 2 times as many orders as Maya. Ahmad served 5 fewer orders

than Maya. How many orders did they each serve?

User NicoKowe
by
8.2k points

1 Answer

9 votes

Total number of orders served by Maya, Ahmad and Joe on Moday = 75

Let the number of orders Maya served be x.

Then :

Number of orders Joe served = 2x

Number of orders Ahmad served = x - 5

This can be written in an equation as :


\tt \: 2x + x - 5 + x = 75


= \tt 4x - 5 = 75


= \tt 4x = 75 + 5


= \tt 4x = 80


= \tt \: x = (80)/(4)


= \tt \: x = 20

Which means :

Number of orders Joe served :

= 2 × 20

= 40

Thus, Joe served 40 orders.

Number of orders Maya served = 20

Number of orders Ahmad served :

= 20 - 5

= 15

Thus, Ahmad served 15 orders.

Therefore,

  • Maya served 20 orders
  • Ahmad served 15 orders
  • Joe served 40 orders.
User DChaplin
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories