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2.5 Parallel and perpendicular lines: Problem 5

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Find an equation for the line passing through the point (2Ė5) and perpendicular to the line y = 5x - 18.
Y

User Ozgeneral
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Final answer:

To find the equation for the line passing through a point and perpendicular to a given line, we find the negative reciprocal of the slope of the given line and use the point-slope form of a line.


Step-by-step explanation:

To find an equation for the line passing through the point (2,-5) and perpendicular to the line y=5x-18, we know that the slope of the new line will be the negative reciprocal of the slope of the given line. The given line has a slope of 5, so the perpendicular line will have a slope of -1/5. Using the point-slope form of a line, we can write the equation as: y - y1 = m(x - x1), where m is the slope and (x1, y1) is the given point. Plugging in the values, we have:

y - (-5) = -1/5(x - 2)

Expanding and simplifying, the equation for the line is y = -1/5x - 3.4.


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User Hart CO
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