Question

Pls help!!

1000 L of nitrogen and 2400 L of hydrogen are mixed to produce ammonia. The volume of ammonia produced is

A. 1200 L

B. 1000 L

C. 2400 L

D. 1600 L

Answer 1

Answer: D. 1600 L

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}`

`\text{Number of moles of nitrogen}==(1000L)/(22.4L)=44.6moles`

`\text{Number of moles of hydrogen}==(2400L)/(22.4L)=107.1moles`

`N_2(g)+3H_2(g)\rightarrow 2NH_3(g)`

According to stoichiometry :

3 moles of
`H_2` require 1 mole of
`N_2`

Thus 107.1 moles of
`H_2` will require=
`(1)/(3)* 107.1=35.7moles` of
`N_2`

Thus
`H_2` is the limiting reagent as it limits the formation of product and
`N_2` is the excess reagent.

As 3 moles of
`H_2` give = 2 moles of
`NH_3`

Thus 107.1 moles of
`H_2` give =
`(2)/(3)* 107.1=71.4moles` of
`NH_3`

Volume of
`NH_3=moles* {\text {Molar volume}}=71.4moles* 22.4L/mol=1600L`

Thus volume of ammonia produced is 1600 L