Question

What is the current in a circuit that is powered by a 6.0 V battery and

connected in series by a 2.0 S resistor and a 12.0 Q resistor?
OA. 84.0 A
OB. 3.0 A
C. 0.43 A
D. 0.50 A

Answer 1

The current in the circuit is approximately 0.43 A.

Step-by-step explanation:

The current in a circuit can be calculated using Ohm's law, which states that the current (I) is equal to the voltage (V) divided by the total resistance (R).

In this case, the circuit is connected in series, so the total resistance is the sum of the individual resistances:

Total resistance (R) = 2.0 S + 12.0 Q = 2.0 Ω + 12.0 Ω = 14.0 Ω

Plugging the values into Ohm's law, we get:

Current (I) = Voltage (V) / Total resistance (R) = 6.0 V / 14.0 Ω ≈ 0.43 A

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