Final answer:
The question addresses a physics problem related to a perfectly inelastic collision where momentum is conserved. It seeks the final velocity after a bullet embeds itself into a block. However, with the given information, the final velocity cannot be explicitly determined without additional data.
Step-by-step explanation:
The question involves a collision in which a bullet embeds itself in a wooden block and the two then move together. This is an example of a perfectly inelastic collision, where momentum is conserved. According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. The formula to calculate final velocity (v) after the collision when a bullet of mass m1 embeds into a block of mass m2 is given by (m1*v1 + m2*v2)/(m1 + m2), where v1 is the initial velocity of the bullet and v2 is the initial velocity of the block (which is 0 since the block is initially at rest).
In the provided question, the mass of the bullet m1 is 0.050 kg and its velocity v1 is 909 m/s, while the mass of the block m2 is 5.0 kg and it's at rest with v2 = 0 m/s. Using conservation of momentum, the final combined velocity v can be calculated. However, since no velocity is given after the collision, it cannot be specified in this case. Typically, this is the kind of problem where you would solve for v given these initial conditions.