Question

1.40 L solution was made by mixing 69.3 mL of dioxane, Which has a density of 1.03 g/mL, and 1.3 L of Toluene, Which has a density of 0.87 g/mL. Calculate the volume percent of dioxane in the solution. Be sure your answer has the right number of significant digits.? %(v/v)

Answer 1

To calculate the volume percent of dioxane we will apply the following formula:

`Volumepercent=\frac{\text{Volume of solute}}{Volume\text{ of solution}}*100`

In this case, the solute will be dioxane, and the volume will be 69.3 mL.

To calculate the volume of solution we will sum both volumes:

Volume of solution = Volume of dioxane + Volume of Toluene

Volume of solution = 69.3 mL + 1300 mL

Volume of solution = 1369.3 mL

`Volumepercent=\frac{\text{6}9.3\text{ mL}}{1369.3\text{ mL}}*100\text{ = 5.1}`

We are given all the data with a significant digit, therefore we must report the result also with a significant digit. So the answer will be.

The volume percent of dioxane in the solution is 5.1 %(v/v)