Answer:
-3, 0, 5 (multiplicity 2)
Explanation:
You want the real solutions of f(x) = 0, given the graph of f(x).
Graph
The value of f(x) is zero where its graph intersects the x-axis (the line y=0). Those intercept points are x = -3, 0, and 5. The graph "touches" the x-axis at x = 5, but does not cross. This indicates there is a zero of even degree at that location.
The three distinct solutions to f(x) = 0 are x = -3, 0, and +5.
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Additional comment
It can be important to know that the solution x = 5 is a root of multiplicity 2. This comes into play when you want to write the equation for the function shown in the graph. It means the factor (x-5) of the function has an exponent of 2. The equation for the function is shown in the attachment. Each root 'p' means (x -p) is a factor of f(x).
The three turning points shown in the graph mean the minimum degree polynomial that will describe this function is degree 3+1 = 4. Such a polynomial will have 4 roots. The number of roots is equal to the degree. In general, some or all of the roots may be complex. Here, they are all real. While we can say the function has two of its four roots at x=5, we are describing x = 5 as one of the three distinct solutions to f(x) = 0.
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