Final answer:
To find the results of the indicated operations with complex numbers z1=(3-i) and z2=-i, we multiply z1 and z2 to get i, divide z1 by z2 to get 1+3i, add z1 and z2 to get 2-i, and subtract z2 from z1 to get 3+i.
Step-by-step explanation:
To complete the indicated operations with complex numbers, we will use the given values of z1=3-i and z2=-i.
- To multiply z1 and z2, we multiply their real and imaginary parts separately. Multiplying (3)(0) and (-1)(-1), we get a real part of 0 and an imaginary part of 1. So z1*z2 = 0 + i = i.
- To divide z1 by z2, we multiply both the numerator and denominator by the complex conjugate of z2. The complex conjugate of -i is -i itself. So, (3-i)/(-i) = ((3-i)(-i))/((-i)(-i)) = (-3i+i²)/(i²) = (-3i-1)/(-1) = 3i+1 = 1+3i.
- To add z1 and z2, we add their real parts and imaginary parts separately. Adding 3 and 0, we get a real part of 3. Adding -1 and -i, we get an imaginary part of -1-i. So z1+z2 = 3 + (-1-i) = 2-i.
- To subtract z2 from z1, we subtract their real parts and imaginary parts separately. Subtracting -1 from 3, we get a real part of 4. Subtracting -i from -1, we get an imaginary part of -1+i. So z1-z2 = 4 + (-1+i) = 3+i.