Question

Maria invested her savings in two investment funds. The amount she invested in Fund A was $7000 less than the amount she invested in Fund B. Fund Areturned a 7% profit and Fund B returned a 3% profit. How much did she invest in Fund B, if the total profit from the two funds together was $1610?

Answer 1

It is given that,

The amount she invested in Fund A was $7000 less than the amount she invested in Fund B.

So, A=B-7000

And it is given that, Fund A returned a 7% profit and Fund B returned a 3% profit.

The total profit from the two funds together was $1610.

It can be written as,

7% of A +3% of B=1610

Substitute A=B-7000, we get

7% of (B-7000) +3% of B=1610

On solving we get,

`\begin{gathered} (7)/(100)(B-7000)+(3)/(100)B=1610 \\ (7)/(100)B-490+(3)/(100)B=1610 \\ (10)/(100)B-490=1610 \\ (1)/(10)B=1610+490 \\ (1)/(10)B=2100 \\ B=21000 \end{gathered}`

Hence, the investment in fund B is $21,000.