Question

a goblet contains 3 red balls, 2 green balls, and 5 blue balls. if we choose a ball, then another ball without putting the first one back in the goblet, what is the probability that the first ball will be red and the second will be blue? 3/20

Answer 1

Answer:
`(1)/(6)`

Explanation:

The chance of the first ball being red is
`(3)/(10)`.

The chance for the second ball being blue is
`(5)/(9)`, as the red ball is not added back in. To find the chance of both of these happening, you multiply them together.

`(3)/(10)` ·
`(5)/(9)` =
`(15)/(90)` which simplifies to
`(1)/(6)`.