The predicted phenotypic ratio of the offspring is 4:0 for yellow seed color.
To predict the phenotypic ratio of the offspring based on seed color in a cross between a homozygous green seed pea plant (yy) and a heterozygous yellow seed pea plant (Yy), you can use Punnett squares. Here are the steps:
1. Determine the genotypes of the parent plants:
- Homozygous green seed pea plant (parent 1): yy
- Heterozygous yellow seed pea plant (parent 2): Yy
2. Set up a Punnett square to cross these two parent genotypes
Parent 1 (yy)
↓
Parent 2 (Yy)
3. Fill in the Punnett square by combining the alleles from each parent:
Parent 1 (yy)
↓
Parent 2 (Yy)
--------------
Yy | Yy
Yy | Yy
4. Analyze the genotypes of the offspring:
- 4 offspring genotypes are Yy (heterozygous yellow seed).
5. Determine the phenotypes based on the genotypes:
- Yy genotypes result in yellow seed color.
6. Calculate the phenotypic ratio by counting the number of each phenotype:
- Yellow seed (Yy): 4
Now, you have the phenotypic ratio of the offspring based on seed color:
- Yellow seed (Yy): 4
Since there are no green seed alleles (yy) in the offspring, they will all have yellow seed color, as yellow (Y) is dominant to green (y).