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1. 2x-y=0

X+3y=-14


2. Write the equation of the line in slope intercept form that goes through the point (7,2) and has a slope of 4.

3. 4-5x+3=4x-2

Show steps, thx:)

User Thodg
by
7.8k points

1 Answer

9 votes

Answer:

(1)
(x,y) = (-2,-4)

(2)
y = 4x -26

(3)
x = 1

Explanation:

(1):


2x - y = 0


x + 3y = -14

Required: Solve for x and y

Make x the subject in
x + 3y = -14


x = -3y - 14

Substitute -3y - 14 for x in the first equation


2x - y = 0


2(-3y-14) - y = 0

Open bracket


-6y - 28 - y = 0

Collect Like Terms


- y-6y = 28


-7y = 28

Divide both sides by -7


y = -4

Substitute -4 for y in
2x - y = 0


2x - (-4) = 0


2x + 4 = 0

Collect Like Terms


2x = -4

Divide by 2


x = -2

Hence, the solution is:


(x,y) = (-2,-4)

(2):


(x_1,y_1) = (7,2) -- points


m = 4 --- slope

Required: Determine the line equation

This is calculated using:


y = m(x - x_1) + y_1

This gives:


y = 4(x - 7) + 2

Open bracket


y = 4x - 28 + 2


y = 4x -26

(3)


4 - 5x + 3 = 4x - 2

Required: Solve for x

Collect Like Terms


- 5x -4x = - 2-3-4


-9x = -9

Divide both sides by -9


x = 1

User Mspapant
by
7.9k points

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