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Let p: A student plays basketball. (11 student) Let q: A student plays tennis. (21 student) Intersect (4 student) How many students play both basketball and tennis? a. 4 b. 8 c. 32 d. 36

User Roy Reiss
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To find the number of students who play both basketball and tennis, we need to find the intersection of the two sets. By comparing the given sets A and B, we find the common elements and determine that 3 students play both basketball and tennis.

In this question, we are given two sets of students: those who play basketball (A) and those who play tennis (B), and we are asked to find the number of students who play both basketball and tennis, which is the intersection of sets A and B.

From the given information, we have set A = {2, 4, 6, 8, 10, 12, 14, 16, 18} and set B = {14, 15, 16, 17, 18, 19}.

To find the intersection of sets A and B, we need to find the common elements between the two sets. By comparing the two sets, we can see that the common elements are {14, 16, 18}.

Therefore, the number of students who play both basketball and tennis is 3.

Learn more about Intersection of Sets

User Mordaroso
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