Answer:
A. 2-Bromopropane
Step-by-step explanation:
Propene is the second member of the alkene group with the chemical formula; C3H6. It reacts with hydrogen bromide (HBr), which is an acidic compound to form an alkylbromide.
In this reaction, the formation of a major product is in accordance with Markovnikov's rule, which emphasizes that hydrogen will be added to the carbon with more hydrogen. Hence, the bromide ion of HBr will be added to the second carbon atom of the alkene (propene), to form 2-bromopropane as a major product.
The reaction is as follows:
CH3CH=CH2 (propene) + HBr → CH3CHBrCH3 (2-bromopropane).