Final answer:
The time spent moving upward in a 0.6-meter vertical jump is approximately 0.44 seconds, and the hang time—both upward and downward combined—is approximately 0.88 seconds.
Explanation:
To determine the time spent moving upward in a vertical jump, we can use the kinematic equation for vertical motion:
![\[ h = (1)/(2)gt^2 \]](https://img.qammunity.org/2024/formulas/physics/high-school/tesehpuse3tqe1ij44p6qa4xsnnazzn2zn.png)
Where:
h is the jump height (0.6 meters),
g is the acceleration due to gravity (approximately 9.8 m/s²), and
t is the time spent moving upward.
Rearranging the equation to solve for t , we get:
![\[ t = \sqrt{(2h)/(g)} \]](https://img.qammunity.org/2024/formulas/physics/high-school/46p9ajv3pmfsfi267dk2zmiehxchorqes7.png)
Substituting the given values, we find t to be approximately 0.44 seconds.
To find the total hang time, we double this time since it includes both the upward and downward motion. Therefore, the hang time is approximately 0.88 seconds.
Understanding the physics behind vertical jumps involves recognizing that the time spent ascending is determined by the initial velocity imparted to the body, which is influenced by factors such as leg strength and technique.
In this case, the calculated time provides insight into the brief duration an athlete spends in the air during a 0.6-meter jump. These calculations are crucial for athletes and coaches in various sports, helping them optimize training regimens and improve performance in activities requiring explosive vertical movements.