Question

At a local coffee shop, they have a members-only service that offers two

plans. The first plan costs $1.99 per coffee plus an initial fee of $30. The second
plan costs $2.99 per coffee plus an initial fee of $15. How many coffees con you
get where the two plans would cost the same?
​

Answer 1

Explanation:

To find the number of coffees at which the two plans would cost the same, you can set up an equation. Let's say \(x\) represents the number of coffees.

For the first plan: Cost = \(1.99x + 30\)

For the second plan: Cost = \(2.99x + 15\)

To find when the costs are equal, set these two equations equal to each other and solve for \(x\):

\(1.99x + 30 = 2.99x + 15\)

Now, subtract \(1.99x\) from both sides:

\(30 = 1x + 15\)

Subtract 15 from both sides:

\(15 = 1x\)

So, \(x = 15\).

You can get the same cost for both plans after purchasing 15 coffees.To find the number of coffees at which the two plans would cost the same, you can set up an equation. Let's say \(x\) represents the number of coffees.

For the first plan: Cost = \(1.99x + 30\)

For the second plan: Cost = \(2.99x + 15\)

To find when the costs are equal, set these two equations equal to each other and solve for \(x\):

\(1.99x + 30 = 2.99x + 15\)

Now, subtract \(1.99x\) from both sides:

\(30 = 1x + 15\)

Subtract 15 from both sides:

\(15 = 1x\)

So, \(x = 15\).

You can get the same cost for both plans after purchasing 15 coffees.