Question

A spring vibrates 24,000 times in 12 seconds. What are the frequency and period? a) Frequency = 2,000 Hz, Period = 0.0005 s b) Frequency = 12,000 Hz, Period = 0.002 s c) Frequency = 1,000 Hz, Period = 0.001 s d) Frequency = 2,400 Hz, Period = 0.004 s

Answer 1

In the given question, the spring vibrates 24,000 times in 12 seconds which implies a frequency of 2,000 Hz and a period of 0.0005 seconds based on the formulas f = vibrations / time and T = 1 / f.

Step-by-step explanation:

The question relates to the principles of oscillations and waves, specifically frequency and period, parts of simple harmonic motion. The frequency (f) is defined as the number of oscillations per unit time. To calculate it, you'll divide the number of vibrations (24,000 times) by the total time (12 seconds). So, f = 24,000 / 12 = 2,000 hertz (Hz).

The period (T) is the time for one complete cycle of oscillation, and it's the reciprocal of the frequency. It is calculated as T = 1 / f. Hence T = 1 / 2,000 = 0.0005 seconds (s). Therefore, the correct answer is a) Frequency = 2,000 Hz, Period = 0.0005 s.

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