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Solve for D


2d2+5d–12=0

2 Answers

6 votes

Answer: d=3/2

Explanation:

User Wallyqs
by
7.4k points
1 vote

Answer:


d = (3)/(2)


d = -4

Explanation:

Given quadratic equation:


2d^2 + 5d - 12 = 0

To solve the given quadratic equation for d, we can use the method of factoring.

To factor a quadratic equation in the form ax² + bx + c = 0, first identity the coefficients a, b and c.

In the case of 2d² + 5d - 12 = 0:

  • a = 2
  • b = 5
  • c = -12

Find two numbers that multiply to "ac" (in this case, 2 · (-12) = -24) and sum to "b" (which is 5).

The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. Among these, the factor pair that sums to 5 is -3 and 8.

Rewrite the middle term "b" using these two numbers:


2d^2-3d+8d - 12 = 0

Factor the first two terms and the last two terms separately:


d(2d-3)+4(2d - 3) = 0

Factor out the common term (2d - 3):


(d+4)(2d-3)=0

Apply the zero-product property by setting each factor equal to zero and solving for d:


d+4=0 \implies d = -4


2d-3=0 \implies d=(3)/(2)

Therefore, the solutions to the equation are:


\large\boxed{\boxed{d = (3)/(2)\;\;\textsf{and}\;\;d = -4}}

User Aashreys
by
7.2k points