Question

the horizontal surface on which the block of mass 6.6 kg slides is frictionless. The force of 56 N acts on the block and horizontal direction of the force of 168 N on the block, an angle at shelf below. what is the magnitude of the resulting acceleration of the block? Acceleration of gravity is 9.8

Answer 1

Step-by-step explanation:

We can use Newton's Second Law to solve this problem.

F = ma

We need to find the net force in the horizontal direction. We already know that a force of 56 N acts on the block in the horizontal direction. However, there is another force at an angle. To find the horizontal force of this force, we need to break it into its horizontal and vertical components.

Assuming that the angle from the horizontal is 60º, we can find the horizontal component of the force with 168cos(60º) = 84 N.

Assuming that this force is acting on the block opposite of the 56 N force, that means that the 84N force is negative.

F = ma

56 + (-84) = 6.6a

-28 = 6.6a

a = -4.24 m/s²