Answer:
there will be no moles of F2 left over as it is the reactant in excess.
Step-by-step explanation:
To determine how many moles of the reactant in excess will be left over after the reaction is complete, we need to compare the stoichiometry of the balanced equation to the initial amounts of the reactants.
In the balanced equation S8 + 24 F2 → 8 SF6, we see that 1 mole of S8 reacts with 24 moles of F2 to produce 8 moles of SF6.
We have 48 moles of S8 and 48 moles of F2.
Since the ratio of S8 to F2 is 1:24, we need 24 times more moles of F2 than S8 to react completely.
Therefore, we would need 48 x 24 = 1152 moles of F2 to react with 48 moles of S8.
Since we only have 48 moles of F2, which is less than the required amount, F2 is the reactant in excess.
To find out how many moles of F2 will be left over, we can subtract the amount of F2 that reacted from the initial amount of F2.
For every mole of S8 that reacts, 24 moles of F2 react.
So, for 48 moles of S8, 48 x 24 = 1152 moles of F2 will react.
Therefore, the number of moles of F2 left over after the reaction is complete is 48 - 1152 = -1104 moles.
However, negative moles do not have a physical meaning. So, we can conclude that there will be no F2 left over after the reaction is complete.