Final answer:
The value of f(1) for the function f(x) = 0.25e-0.25x is approximately 0.194. This is found by plugging x = 1 into the function and simplifying.
Step-by-step explanation:
The piecewise defined function in your question is f(x) = 0.25e-0.25x where x is at least zero. To find the value of f(1), we just need to substitute x = 1 into the function.
So, f(1) = 0.25e(-0.25)(1). Using a calculator, we find that e^(-0.25) is approximately 0.778800783, so we get f(1) = 0.25 * 0.778800783 = 0.194700196, approximately.
Therefore, the value of f(1) for this function is approximately 0.194. Remember, this function describes the exponential decay of the variable x, and is often used in physics and engineering.
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