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The standard deviation of the scores on a skill evaluation test is 497

points with a mean of 1754
points.

If 302 tests are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 44
points? Round your answer to four decimal places.

1 Answer

2 votes

Answer:

497/√302 = 49.7

z-score = (44-0)/49.7 = 0.88

Probability = 0.8133

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