Question

A4 resistor is connected to a 12-V battery. What is thecurrent through the battery? What is the power dissipatedby the resistor?

Answer 1

According to Ohm's law,

So the current is given as,

The power dissipated by the resistor is given as,

Hence, 3 A of current passes through the resistor and power dissipated is 36 W.

`\begin{gathered} P=I^2R \\ =(3A)^2*4\text{ }\Omega \\ =36\text{ W} \end{gathered}`

`\begin{gathered} I=(V)/(R) \\ I=\frac{12\text{ V}}{4\text{ }\Omega} \\ I=3\text{ A} \end{gathered}`

`V=IR`