Answer: Explanation below.
Explanation:
To evaluate the function at 0.125-second intervals from 0 through 1 seconds, we need to substitute the values of t = 0, 0.125, 0.25, 0.375, 0.5, 0.625, 0.75, 0.875, and 1 in the given function and calculate the corresponding values of h(t).
Using the function h(t) = 12sin(4πx) + 12, we get:
At t = 0 seconds, h(0) = 12sin(4π(0)) + 12 = 12sin(0) + 12 = 12 + 0 = 12
At t = 0.125 seconds, h(0.125) = 12sin(4π(0.125)) + 12 ≈ 18.99
At t = 0.25 seconds, h(0.25) = 12sin(4π(0.25)) + 12 ≈ 23.39
At t = 0.375 seconds, h(0.375) = 12sin(4π(0.375)) + 12 ≈ 24.73
At t = 0.5 seconds, h(0.5) = 12sin(4π(0.5)) + 12 = 12sin(2π) + 12 = 12 + 0 = 12
At t = 0.625 seconds, h(0.625) = 12sin(4π(0.625)) + 12 ≈ 4.60
At t = 0.75 seconds, h(0.75) = 12sin(4π(0.75)) + 12 ≈ -0.80
At t = 0.875 seconds, h(0.875) = 12sin(4π(0.875)) + 12 ≈ -3.91
At t = 1 second, h(1) = 12sin(4π(1)) + 12 = 12sin(4π) + 12 = 12 + 0 = 12
Thus, the table of values for h(t) at 0.125-second intervals from 0 through 1 seconds is:
t | h(t)
___________
0 12
0.125 18.99
0.25 23.39
0.375 24.73
0.5 12
0.625 4.60
0.75 -0.80
0.875 -3.91
1 12