Answer:
To calculate the amount of heat absorbed by the ice, we need to use the equation:
Q = m * ΔHf
where Q is the heat absorbed by the ice, m is the mass of the ice, and ΔHf is the heat of fusion of the ice, which is 334 J/g.
First, we need to calculate the amount of heat lost by the water:
Q = m * c * ΔT
where Q is the heat lost by the water, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the temperature change of the water.
We know that the mass of the water is 100 g, c is 4.18 J/g-°C, and ΔT is 5°C, so:
Q = 100 g * 4.18 J/g-°C * 5°C
Q = 2090 J
This means that the water lost 2090 J of heat, which was absorbed by the ice. Now we can calculate the amount of heat absorbed by the ice:
Q = m * ΔHf
We know that the mass of the ice is 10 g and the heat of fusion of the ice is 334 J/g, so:
Q = 10 g * 334 J/g
Q = 3340 J
Therefore, the amount of heat absorbed by the ice is 3340 J, which is equivalent to 3.34 kJ (kilojoules). The closest answer choice is 2.09 kJ, but that is not the correct answer.