Question

how many liters of a 25 % 25%, percent saline solution must be added to 3 33 liters of a 10 % 10, percent saline solution to obtain a 15 % 15, percent saline solution?'

Answer 1

Here, x represents the amount (in liters) of the 25% saline solution to be added.

We can see that the 25% saline solution needs to be mixed with the 10% saline solution to obtain a mixture that is 15% saline. The ratio of the volumes of the 25% and 10% solutions can be found by subtracting the concentrations of the two solutions and dividing by the difference between the desired concentration and the concentration of the 10% solution:

x / (3.33 - x) = (15 - 10) / (25 - 10) = 5/15 = 1/3

Multiplying both sides by 3.33 - x, we get:

x = (1/3) (3.33 - x)

Multiplying both sides by 3, we get:

3x = 3.33 - x

Solving for x, we get:

x = 0.833 liters

Therefore, 0.833 liters of the 25% saline solution must be added to 3.33 liters of the 10% saline solution to obtain 4.163 liters of a 15% saline solution.

Explanation: