Question

Sharon and Kaylyn are playing air hockey. Sharon hits the hockey puck sending it at a velocity of 6 m/s and it hits Kaylyn's puck Both hockey pucks have a mass of 0.3 kg Sharon's puck stops after it hits Kaylyn's puck According to the law of conservation of momentum, what should the resulting velocity of Kaylyn's puck be if it. was at rest before colliding with Sharon's puck?

A. Equal to the velocity of Sharon's puck before they collided
B. Twice the velocity of Sharon's puck before they collided
C. Half the velocity of Sharon's puck before they collided
D. Equal to the velocity of Sharon's puck ball after they collided​

Answer 1

Step-by-step explanation:

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. We can use this principle to determine the resulting velocity of Kaylyn's puck after the collision.

Before the collision, Sharon's puck has a momentum of:

p1 = m1 * v1 = 0.3 kg * 6 m/s = 1.8 kg m/s

where m1 is the mass of Sharon's puck and v1 is its velocity.

Kaylyn's puck is at rest before the collision, so its momentum is:

p2 = m2 * v2 = 0.3 kg * 0 m/s = 0

where m2 is the mass of Kaylyn's puck and v2 is its velocity.

After the collision, Sharon's puck is at rest, so its momentum is:

p1' = m1 * v1' = 0.3 kg * 0 m/s = 0

where v1' is the velocity of Sharon's puck after the collision.

The total momentum after the collision is the momentum of Kaylyn's puck:

p2' = m2 * v2'

where v2' is the resulting velocity of Kaylyn's puck after the collision.

Using the conservation of momentum principle, we can write:

p1 + p2 = p1' + p2'

Substituting the values we have calculated:

1.8 kg m/s + 0 = 0 + 0.3 kg * v2'

Solving for v2':

v2' = (1.8 kg m/s) / (0.3 kg) = 6 m/s

Therefore, the resulting velocity of Kaylyn's puck after the collision is 6 m/s, which is equal to the velocity of Sharon's puck before they collided. The correct answer is option A.