Question

Find the product of (7-8x)(3x^3-2x^2+x)

Answer 1

Explanation:

To find the product of (7-8x)(3x^3-2x^2+x), we need to use the distributive property of multiplication over addition/subtraction.

First, let's distribute the 7 across the second factor:

(7)(3x^3) - (7)(2x^2) + (7)(x)

This simplifies to:

21x^3 - 14x^2 + 7x

Next, we need to distribute the -8x across the second factor:

(-8x)(3x^3) + (-8x)(-2x^2) + (-8x)(x)

This simplifies to:

-24x^4 + 16x^3 - 8x^2

Now, we can combine the two simplifications:

(7-8x)(3x^3-2x^2+x) = 21x^3 - 14x^2 + 7x - 24x^4 + 16x^3 - 8x^2

Finally, we can combine like terms to simplify the expression:

-24x^4 + 37x^3 - 22x^2 + 7x

Therefore, the product of (7-8x)(3x^3-2x^2+x) is -24x^4 + 37x^3 - 22x^2 + 7x.