Answer:
The inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.
Explanation:
It seems like there are multiple questions combined in this one prompt. I will break them down and provide solutions for each one.
Solution for O x≤-3 or 2 Ox<-3 or 2 O-3≤x≤2 or x > 7:
To find the solution for this inequality, we need to solve each part separately and then combine the solutions using the union (OR) operation.
a) x ≤ -3: This part is already solved for x. The solution is x ≤ -3.
b) 2x < -3: We divide both sides by 2 to isolate x and get x < -3/2.
c) 2 ≤ x ≤ -3: This is not possible as there is no number that is both greater than or equal to 2 and less than or equal to -3.
d) x > 7: This part is already solved for x. The solution is x > 7.
The solution to the entire inequality is the union of these solutions: x ≤ -3 OR x < -3/2 OR x > 7.
Solution for x²+x-6 < 0
To solve this quadratic inequality, we can factor it as (x-2)(x+3) < 0 and use the sign chart method.
We create a sign chart for the expression (x-2)(x+3) and test the sign of the expression in each interval
-3 2
---|-------|---
- +
(x-2) - 0 + +
(x+3) - - - 0 +
-------------
- + - 0 +
The sign chart tells us that the expression is negative when x is between -3 and 2. Therefore, the solution to the inequality is -3 < x < 2.
Solution for x-7 ≤ 50₂
It seems like the expression "50₂" is intended to represent the number 50 in base 2 (binary). To convert this number to base 10 (decimal), we can write 50₂ as
50₂ = 12^5 + 12^4 + 02^3 + 02^2 + 12^1 + 02^0 = 32 + 16 + 2 = 50
Therefore, the inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.