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you push a 15.0 kg box across the floor at a steady speed of 1.25 m/s for 16.0 s. the coefficient of kinetic friction between the box and the floor is 0.680. what is your power output?

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The power output of pushing a 15.0 kg box across the floor at a steady speed of 1.25 m/s for 16.0 s, with a coefficient of kinetic friction of 0.680, can be calculated using the formula:



Power = Force x Velocity



Force = mass x acceleration due to friction



Acceleration due to friction = coefficient of kinetic friction x gravitational force



Power = (15.0 kg x 0.680 x 9.8 m/s2) x (1.25 m/s)

Power = 128.4 Watts



Therefore, the power output of pushing the box for 16.0 s is 128.4 Watts.

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