We are given that d = 10 log(K) where K is a constant and the sound intensity is 1000 times the value of K.
So, we can write I = 1000K
Substituting this value in the equation for d, we get:
d = 10 log(1000K)
d = 10 (log 1000 + log K)
d = 10 (3 + log K)
d = 30 + 10 log K
Since K is a constant, we can assume it to be 1.
Therefore, d = 30 + 10 log 1 = 30
So, an audio source whose sound intensity is 1000 times the value of K produces 30 decibels of sound.
Therefore, the answer is option G) 30.