Question

Could someone help me quickly please?

Answer 1

Answer: 65 advance tickets

Explanation:

Answer 2

Advance tickets sold: 30

Same-day tickets sold: 25

Explanation:

So, let's assume that the number of advance tickets is the variable
`x`, and the number of same-day tickets is
`y`.

Since the cost of advance tickets is $25 dollars, we can show that using
`25x`, and the cost of same-day tickets is $35, we can show that with
`35y`. The total cost of the tickets is $1625 and the total number of tickets is 55.

Now, let's form a system of equations with this information.

`25x+35y=1625\\x+y=55`

Step 1: Rearrange equation so that it solves for a variable

`x+y=55` can be rewritten as
`y=-x+55`

Step 2: Substitute

`y=-x+55`, so, we can write this in the first equation as:
`25x+35(-x+55)=1625`

Step 3: Simplify

`25x-35x+1925=1625\\-10x=-300\\x=30`

So the number of advance tickets sold are 30.

Now, let's solve for the number of same-day tickets sold.

Step 4: Solve for y

Using our equation from above (
`y=-x+55`), we can substitute the value that we solved for (
`x=30`) to solve for the variable y.

`y=-30+55\\y=25`

The number of same-day tickets sold are 25.

Hope this helped ya :)