175k views
0 votes
Pls help. grades due today. teacher hasnt taught me this

Pls help. grades due today. teacher hasnt taught me this-example-1
User Spydon
by
8.1k points

1 Answer

6 votes

Answer:

5624.22 feet

Explanation:

You want to know the distance from a skyscraper 1465 ft tall to a point where the angle of elevation to its top is 14.6°.

Tangent

The tangent relation tells you ...

Tan = Opposite/Adjacent

Application

The distance between buildings is the side of the right triangle adjacent to the angle of elevation. The height of skyscraper B is the side opposite the angle of elevation. Using the tangent relationship, we can find the distance d between the buildings as ...

tan(14.6°) = 1465/d

c = 1465/tan(14.6°) ≈ 5624.22 . . . ft

The distance from A to B is about 5624.22 feet.

<95141404393>

Pls help. grades due today. teacher hasnt taught me this-example-1
Pls help. grades due today. teacher hasnt taught me this-example-2
User Ken Liu
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories