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Pls help. grades due today. teacher hasnt taught me this

Pls help. grades due today. teacher hasnt taught me this-example-1
User Spydon
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1 Answer

6 votes

Answer:

5624.22 feet

Explanation:

You want to know the distance from a skyscraper 1465 ft tall to a point where the angle of elevation to its top is 14.6°.

Tangent

The tangent relation tells you ...

Tan = Opposite/Adjacent

Application

The distance between buildings is the side of the right triangle adjacent to the angle of elevation. The height of skyscraper B is the side opposite the angle of elevation. Using the tangent relationship, we can find the distance d between the buildings as ...

tan(14.6°) = 1465/d

c = 1465/tan(14.6°) ≈ 5624.22 . . . ft

The distance from A to B is about 5624.22 feet.

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Pls help. grades due today. teacher hasnt taught me this-example-1
Pls help. grades due today. teacher hasnt taught me this-example-2
User Ken Liu
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