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a Toyota Celica, travelling initially at 26.9 m/s [S], comes to a stop in 2.61 s. The mass of the car with the driver is 1.18 × 103 kg. Calculate the car’s acceleration.

User Mseery
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The initial velocity of the car is 26.9 m/s [S], and the final velocity is 0 m/s [S]. The time taken for the car to come to a stop is 2.61 s. Using the formula:

acceleration = (final velocity - initial velocity) / time

we can find the car's acceleration:

acceleration = (0 m/s - 26.9 m/s) / 2.61 s

acceleration = -10.305 m/s^2

The negative sign indicates that the car is decelerating, or slowing down.

To calculate the force acting on the car during the deceleration, we can use Newton's second law:

force = mass x acceleration

force = (1.18 × 10^3 kg) x (-10.305 m/s^2)

force = -12,166.1 N

The force acting on the car during deceleration is -12,166.1 N, or approximately 12.2 kN.

User Christopher John
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