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A 65 kg-mass person stands at the end of a diving board, 1.5 m from the board's pivot point. Determine the torque the person is exerting on the board with respect to the pivot point. Show your work.

User Cdeerinck
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Answer:

Step-by-step explanation:

The torque is given by the formula:

τ = F × r × sin(θ)

where τ is the torque, F is the force applied, r is the distance between the force and the pivot point, and θ is the angle between the force and the lever arm.

In this case, the person's weight is the force being applied, and it can be calculated as:

F = m × g

where m is the mass of the person and g is the acceleration due to gravity (9.81 m/s^2).

F = 65 kg × 9.81 m/s^2 = 637.65 N

The distance between the person and the pivot point is 1.5 m, so r = 1.5 m.

The angle between the person's weight and the lever arm is 90 degrees, so sin(θ) = 1.

Therefore, the torque the person is exerting on the board is:

τ = F × r × sin(θ) = 637.65 N × 1.5 m × 1 = 956.475 N·m

So the person is exerting a torque of 956.475 N·m on the diving board with respect to the pivot point.

User Saeedn
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