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a lion starts at rest 26 m away from a clueless jordan and charges towards him at a constant velocity of 50km/h. it takes jordan 1 s to react to the lion, turn around and begin running at a velocity of 5 m/s towards his vehicle. jordan's land rover is parked 6 m away from him and on the same axis as the lion's charge. if jordan escapes, how far behind him is the lion? if jordan is caught, how far is he from the land rover?''

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Final answer:

Jordan is caught before reaching his vehicle. The lion needs less time to cover the distance between them than Jordan needs to reach his vehicle. Jordan is caught 1.65 meters away from the Land Rover.

Step-by-step explanation:

First, we convert the lion's speed from km/h to m/s: 50 km/h = 50,000 m / 3,600 s = 13.89 m/s. Now, we can calculate the distances each travels before Jordan reacts. The lion travels for 1 second at 13.89 m/s which means it would cover 13.89 m in 1 s. Initially, Jordan was 26 m away, so the distance between them is now 26 m - 13.89 m = 12.11 m.

Jordan's speed is 5 m/s after he starts running. To determine if he can reach the vehicle 6 m away before being caught by the lion, we calculate the time it takes for both to travel the respective distances. Jordan needs 6 m / 5 m/s = 1.2 s to reach the Land Rover. The lion would take 12.11 m / 13.89 m/s = 0.87 s to reach Jordan's initial position.

Since the lion would take less time to reach Jordan than it would take for Jordan to reach his vehicle, Jordan is caught before reaching safety. To see how far from the Land Rover Jordan is when caught, we calculate Jordan's travel distance in 0.87 s, which is 5 m/s * 0.87 s = 4.35 m. Jordan is caught 6 m - 4.35 m = 1.65 m away from the Land Rover.

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