Answer:
Step-by-step explanation:
We can use the following kinematic equation to solve for the time required:
v_f = v_i + at
where:
v_f = final velocity = 25.0 m/s
v_i = initial velocity = 20.0 m/s
a = acceleration = 3.0 m/s^2
t = time
Rearranging the equation to solve for t, we get:
t = (v_f - v_i) / a
Substituting the given values, we get:
t = (25.0 m/s - 20.0 m/s) / 3.0 m/s^2
t = 1.67 s
Therefore, it will take 1.67 seconds for the car to go from a speed of 20.0 m/s to a speed of 25.0 m/s, assuming a constant acceleration of 3.0 m/s^2.