Question

Find the volume of the triangular prism; do not round.

Answer 1

`\huge\text{Hey there!}`

`\huge\textsf{Find the \boxed{\bf volume} of a triangular prism is:}`

`\mathsf{(1)/(2)(\boxed{\bf b}ase*\boxed{\bf h}eight*\boxed{\bf l}ength) = \boxed{\bf v}olume}`

`\huge\textsf{Your \boxed{\bf equation} should look like:}`

`\mathsf{volume = (1)/(2)(4.4\ m * 2.5\ m* 6.1\ m)}`

`\huge\textsf{\boxed{\bf Step-by-step} explanation can be:}`

`\mathsf{volume = (1)/(2)(4.4\ m * 2.5\ m* 6.1\ m)}`

`\mathsf{volume = (1)/(2)* 4.4\ m * 2.5\ m* 6.1\ m}`

`\mathsf{volume = 0.5* 4.4\ m * 2.5\ m* 6.1\ m}`

`\mathsf{volume = 2.2\ m* 15.25\ m}`

`\mathsf{volume = 33.55}`

`\huge\textsf{Therefore your \boxed{\bf answer} should be:}`

`\huge\boxed{\mathsf{volume = 33.55m^2}}\huge\checkmark`

~
`\frak{Amphitrite1040:)}`

Answer 2

`\boxed{\mathtt{Volume=33.55m^(3)}}`

Explanation:

`\textsf{For this problem, we are asked to find the Volume of a Triangular Prism.}`

`\large\underline{\textsf{What is Volume?}}`

`\textsf{Volume is the amount of space a figure occupies. Volume is measured in Cubic units.}`

`\large\underline{\textsf{We are Given;}}`

`\textsf{The Height is 6.1m. Keep in mind that the Height is the Perpendicular Distance}`

`\textsf{between 2 bases.}`

`\textsf{The base is; (4.4 x 2.5).}`

`\textsf{The Height of the Triangle is 2.5m.}`

`\large\underline{\textsf{Necessary Formulas;}}`

`\mathtt{Volume=(Base) * Height}`

`\mathtt{Area = (1)/(2) (Base * Height)}`

`\large\underline{\textsf{For this Problem;}}`

`\mathtt{Volume=(Triangles' \ Area) * Height}`

`\large\underline{\textsf{The area of a Triangle is;}}`

`\mathtt{Area = (1)/(2) (Base * Height)}`

`\textsf{Find the area of the base first.}`

`\large\underline{\textsf{Substitute;}}`

`\mathtt{Area = (1)/(2) (4.4 * 2.5)}`

`\boxed{\mathtt{Area = 5.5m^(2).}}`

`\textsf{We know the Base, now let's find the volume of the figure.}`

`\large\underline{\textsf{Substitute;}}`

`\mathtt{Volume=5.5 * 6.1}`

`\boxed{\mathtt{Volume=33.55m^(3)}}`