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How long would it take a car from rest and acceleration in a straight line ar 5 metres per sec to cover a dis of 200

User Keeth
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1 Answer

6 votes

Answer:

Step-by-step explanation:

To solve this problem, we can use the following kinematic equation:

d = 1/2at^2 + vt

where d is the distance, a is the acceleration, t is the time, and v is the initial velocity.

We know that the car is starting from rest, so v = 0. We also know that the acceleration is 5 m/s^2 and the distance to be covered is 200 m. Plugging these values into the equation, we get:

200 = 1/2(5)t^2 + 0

Simplifying:

t^2 = 80

Taking the square root of both sides:

t = 8.9 s

Therefore, it would take the car approximately 8.9 seconds to cover a distance of 200 meters from rest with an acceleration of 5 meters per second squared.

User Washcloth
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