To find:-
- The amount of paint required to paint two coats on the wall of a rectangular room of dimensions 14ft × 18ft × 8ft .
Answer:-
We are here given that 1 gallon of paint can be used to paint 400 sq ft. of an area .
There are 4 walls in a room and the area of opposite walls are equal.
So let's find out the area of wall ABCD , its area would be equal to the area of the wall EFGH . So ,
Area of wall ABCD and EFGH :-
Area = lb
Area = 18ft * 8ft
Area = 144ft.²
Therefore area of wall EFGH will also be 144ft.² .
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Again,
Area of wall DAHE and CBGF :-
Here both the areas of the wall would again be equal, as they have same dimensions of 14ft × 8ft .
Area = lb
Area = 14ft * 8ft
Area = 112ft.²
Therefore area of walls DAHE and CBGF is 112ft.²
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Calculating total area of the four walls :-
Total area = 2( 112ft.² + 144ft.² )= 512ft.²
Hence total area of four walls is 512ft.²
Now since there will be two coats of paints , total area to be painted would become double that is 1024ft.²
Now we may use Unitary Method :-
To paint 400ft.² 1 gallon of paint is needed.
To paint 1ft.² 1/400 gallon of paint is needed.
To paint 1024ft.² , 1/400*1024 = 2.56 gallons of paint would be needed.
Hence the total paint required is 2.56 gallons.
and we are done!