Question

A hot air balloon has a volume of 3100 m to the third at 91 degrees Celsius what is the volume if the air cools to 86 degrees Celsius

Answer 1

answer: 3057.44 m^3

Step-by-step explanation:

This is Charles Law which is V1/T1=V2/T2 and temp must be in kelvin

So v2=V1 x T2/T1

v2= 3100 X 359.15 / 364.15 = 3057.44 m^3

t1= 91 +273.15 = 364.15

t2=86+273.15 =359.15