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4 votes
42 grams of nitrogen gas react with

13 grams of hydrogen gas. What is the
limiting reactant and how many grams of
ammonia will be produced?
N2 + 3H22NH3
A) H2; 74 grams NH3 produced
B) H2; 4.3 grams NH3 produced
C) N2; 3.0 grams NH3 produced
D) N2; 51 grams NH3 produced

User Lincolnge
by
8.2k points

1 Answer

5 votes

Answer:

d

Step-by-step explanation:

Nitrogen is the limiting reactant.

42 g N2x (1mole N2/28 g N2) X (2 moles NH3/ 1mole N2) X (17 grams NH3/1mole NH3) = 51 g

13 g H2 x (1 mole H2/2 g H2) X (2 moles NH3/3moles H2) X (17 g NH3/1mole NH3) =73.66g

since 51 is smaller than 73.66 and it started with N2 that is why N2 is the limiting reactant)

User Yves Rochon
by
8.8k points
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