Question

At 19 degrees Celsius a gas exerts 1.92 of pressure at what temperature(in Celsius) will it exert a pressure of 0.45 atm

Answer 1

Answer: -204.48 celsius

Step-by-step explanation:

Gay lussac law P1/T1 = P2/T2

T2 = T1P2/P1

I AM ASSUMING THAT 1.92 IS IN ATMS

Temperature must be in Kelvin

t2= 292.15 x 0.45/1.92 =68.47 K

68.47-273.15 = -204.48 celsius it is a negative number