Question

Which description compares the vertical asymptote(s) of Function A and Function B correctly? Function A: f(x)=1/x−3 Function B: A hyperbola graphed on a grid with the x and y axis beginning at negative ten and increasing in increments of two until reaching ten. The hyperbola, labeled g of x, contains an asymptote at x equals four. The branches of the hyperbola are oriented so they open to the upper right and lower left corners of the asymptote. The lower left branch passes through begin ordered pair zero comma zero end ordered pair as a smooth curve. The upper right branch passes through begin ordered pair eight comma two end ordered pair as a smooth curve. Responses Both functions have a vertical asymptote at x = 4. Both functions have a vertical asymptote at x = 4. Function A has two vertical asymptotes. Function B has one vertical asymptote. Function A has two vertical asymptotes. Function B has one vertical asymptote. Function A has a vertical asymptote at x=−3 . Function B has a vertical asymptote at x = 4. Function A has a vertical asymptote at , x = − 3 , . Function B has a vertical asymptote at x = 4. Function A has a vertical asymptote at x = 3. Function B has a vertical asymptote at x = 4.

Answer 1

The answer is D

Explanation:

Function A

f(x) = 1 / ( x - 3)

The vertical asymptote is the value of x that makes x - 3 = 0 ⇒ x = 3

The vertical asymptote of B is x = 4

So....

Function A has a vertical asymptote at x = 3.

Function B has a vertical asymptote at x = 4.