Question

In the reaction NH3(g) + O2(g) → NO(g) + H₂O(g) How many grams of H₂0 are generated when 1.54 moles of NH3 react?​

Answer 1

Answer: 2.31 mole H2O

Explanation: blance the equation first

4 NH3 + 5O2 --> 4 NO + 6 H20

1.54 moles NH3 x ( 6 mole H20/ 4 moles NH3) X (18 g H20/1mole H20)

2.31 mole H20