Question

Or

A line has a slope of 1 and passes through the point (6,10). Write its equation in slope-intercept form.

Answer 1

`\huge\boxed{\sf y = x + 4}`

Explanation:

Slope = m = 1

Point = (x,y) = (6,10)

Here, x = 6 and y = 10

Slope-intercept equation:

y = mx + c

Where m is slope and c is y-intercept.

Put x, y and m in the above equation.

10 = (1)(6) + c

10 = 6 + c

• Subtract 6 from both sides

10 - 6 = c

c = 4

So,

The slope-intercept form is:

y = (1)x + (4)

y = x + 4

`\rule[225]{225}{2}`